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(a) What is the electric field at the origin? N/C j (b) What would be the force

ID: 2124689 • Letter: #

Question

(a) What is the electric field at the origin?

N/C j    

(b) What would be the force on a charge of -4 nC placed at the origin?

N j    

(c) If this force is due to a charge on the y axis at y = 3 cm, what is the value of that charge?

nC   

Please give exact answers

When a test charge q0 = 11 nC is placed at the origin, it experiences a force of 8 times 10-4 N in the positive y direction. What is the electric field at the origin? What would be the force on a charge of -4 nC placed at the origin? If this force is due to a charge on the y axis at y = 3 cm, what is the value of that charge?

Explanation / Answer

given charge q0 = 11 nC force on test charge F = 8* 10^-4N

electric field at the origin E = F/q0 = 7.273 * 10^ 4 N/C b) if the charge isq= - 4nc force on the charge F = Eq = 7.273 * 10^ 4 N/C * -4nC = -2.909 * 10^-4N ( down ward direction ) c) distance r = 3cm = 0.03m from the coloumb s law E = kq1q2/r2 force on charge - 4nc is = -2.909 * 10^-4N q2 = Er2/kq1 = 2.5 nC in between - 4nc and 2.5 nC there is attractive force.    given charge q0 = 11 nC force on test charge F = 8* 10^-4N

electric field at the origin E = F/q0 = 7.273 * 10^ 4 N/C b) if the charge isq= - 4nc force on the charge F = Eq = 7.273 * 10^ 4 N/C * -4nC = -2.909 * 10^-4N ( down ward direction ) c) distance r = 3cm = 0.03m from the coloumb s law E = kq1q2/r2 force on charge - 4nc is = -2.909 * 10^-4N q2 = Er2/kq1 = 2.5 nC in between - 4nc and 2.5 nC there is attractive force.    = 2.5 nC in between - 4nc and 2.5 nC there is attractive force.