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A car of mass m = 1425 kg is pushed off a cliff of height h =23 m. If the car la

ID: 1743762 • Letter: A

Question

A car of mass m = 1425 kg is pushed off a cliff of height h =23 m. If the car lands a distance of 8 m from the base of thecliff, what was the kinetic energy of the car the instant after itleft the cliff? . Sorry I have no idea how to post the picture with my questionlike everyone else I see on thie website does :). I brand newto the website and this would be my first post. If its neededlet me know and I will try to figure out how to do that as well:) . For the question I know. m=1425 h=23 distance away from cliff when arriving at ground is 8 Vf is going to be 0. . From there, I am at a loss. Any kind of push to send me intothe right direction would be much appreciated. :). A car of mass m = 1425 kg is pushed off a cliff of height h =23 m. If the car lands a distance of 8 m from the base of thecliff, what was the kinetic energy of the car the instant after itleft the cliff? . Sorry I have no idea how to post the picture with my questionlike everyone else I see on thie website does :). I brand newto the website and this would be my first post. If its neededlet me know and I will try to figure out how to do that as well:) . For the question I know. m=1425 h=23 distance away from cliff when arriving at ground is 8 Vf is going to be 0. . From there, I am at a loss. Any kind of push to send me intothe right direction would be much appreciated. :).

Explanation / Answer

h = 1/2 g t2    where h is theheight of the cliff and t the time to reach the ground t = (2 h / g) s = v t   where v is the horizontal speed of the carwhen the cliff and s the distance from the base of the cliff v = s / t = s (g / (2 h) KE = 1/2 m v2 = m s2 g / (4 h)
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