Two parallel plates are .005m apart and are each2m 2 in area. The plates are in

Question

Two parallel plates are .005m apart and are each2m2 in area. The plates are in vaccuum and an electricpotential difference of 10,000V is applied across them. a) Find the capacitance the charge on each plate, the electricfield intensity in the space between tand the stored energy. b) If a dielectric material with dielectric constant K= 80.4is inserted into the gap between the plates, with the electricpotential remaining the same, find the new capacitance, charge oneach plate, electric field intensity and energy stored. Two parallel plates are .005m apart and are each2m2 in area. The plates are in vaccuum and an electricpotential difference of 10,000V is applied across them. a) Find the capacitance the charge on each plate, the electricfield intensity in the space between tand the stored energy. b) If a dielectric material with dielectric constant K= 80.4is inserted into the gap between the plates, with the electricpotential remaining the same, find the new capacitance, charge oneach plate, electric field intensity and energy stored.

Explanation / Answer

Capacitance C = o A / d where o = 8.85 * 10 ^ -12 C ^ 2 / N m ^2           A =area = 2 m ^ 2           d= 0.005 m substitue values we get answer Potential difference V = 10000 V So, charge Q = C V Electric field intensity E = Q / A o Energy stored U = ( 1/ 2) C V ^ 2 (b). dielectric constant k = 80.4 New capacitance C ' = K C Charge on each plate Q ' = C ' V electric field intensity E ' = Q ' / A o energy stored U ' = K U substitue values weget answers energy stored U ' = K U substitue values weget answers

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