Two parallel conducting plates carry equal and opposite charges. The plates are

Question

Two parallel conducting plates carry equal and opposite charges. The plates are large relative to their separation distance, so we can assume the electric field between them is uniform. The potential difference between them is 0.34 V , and the magnitude of the electric field between them is 55 V/m .

Part A

What is the surface charge density on the plates?

Express your answer with the appropriate units.

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Enter your answer using dimensions of electric charge per unit area.

Part B

What is the separation distance?

Express your answer with the appropriate units.

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Part C

How much work is done by the electric field on an electron as it moves from the negative plate to the positive plate?

Express your answer with the appropriate units.

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Two parallel conducting plates carry equal and opposite charges. The plates are large relative to their separation distance, so we can assume the electric field between them is uniform. The potential difference between them is 0.34 V , and the magnitude of the electric field between them is 55 V/m .

Part A

What is the surface charge density on the plates?

Express your answer with the appropriate units.

=

SubmitMy AnswersGive Up

Incorrect; Try Again; 5 attempts remaining

Enter your answer using dimensions of electric charge per unit area.

Part B

What is the separation distance?

Express your answer with the appropriate units.

d=

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Part C

How much work is done by the electric field on an electron as it moves from the negative plate to the positive plate?

Express your answer with the appropriate units.

W=

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Explanation / Answer

Potential Difference = 0.34 V
Electric Field = 55 V/m
(Part A)
Electric Field = /Eo
55 = / 8.85 × 10-12
= 55 * 8.85 × 10-12
= 4.87 * 10^-10 C/m^2
= 0.487 nC/m^2

(Part B)
E.F = Potential Difference / Distance between Plates
Distance between Plates = 0.34 / 55 = 0.00618 m
Distance between Plates = 6.18 mm

(Part C)
Work done = - Change in Potential Energy
Chane in Potential Energy = Charge * Potential Difference between Plates
Charge on Electron is negative.
Work done = - ((-1.6 * 10^-19) * 0.34) J
Work done = 5.44 * 10^-20 J

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