Two oppositely charged but otherwise identical conducting plates of area 2.50 sq
ID: 1515116 • Letter: T
Question
Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of K=3.60. The resultant electric field in the dielectric is 1.20×106 volts per meter.
Compute the magnitude of the charge per unit area on the conducting plate.
sigma=c/m^2
Compute the magnitude of the charge per unit area 1 on the surfaces of the dielectric.
1=c/m^2
Find the total electric-field energy U stored in the capacitor.
u=J
Explanation / Answer
a) the magnitude of the charge per unit area on the conducting plate:
E effective = /(k0)
= 3.6 * 8.854e-12 * 1.20e6 = 3.82*e-5 C/m^2
b) the magnitude of the charge per unit area 1 on the surfaces of the dielectric.
( on the dielectric ) = ( (1/k) -1)
= - 2.75 e-5 C/m^2
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