A tennis player receives a shot with the ball (0.0600 kg) travelinghorizontally

Question

A tennis player receives a shot with the ball (0.0600 kg) travelinghorizontally at 56.0 m/s andreturns the shot with the ball traveling horizontallyat 42.0 m/s in the oppositedirection. (Assume the initial direction of the ball is in the-x direction.) (a) What is the impulse delivered to the ball by the racket?
N·s Direction+x-x

(b) What work does the racket do on the ball?
J (a) What is the impulse delivered to the ball by the racket?
N·s Direction+x-x

(b) What work does the racket do on the ball?
J

Explanation / Answer

I=m(v-u)=0.06(42-(-56))=5.88Ns The work done=change in KE W=KE=1/2*m1v12-1/2*m2v22 W=1/2*0.06*562-1/2*0.06*422J Hence we get by it. W=1/2*0.06*562-1/2*0.06*422J Hence we get by it.

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