A tennis ball of mass 6.0?10 ?2 kg and speed 29m/s strikes a wall at a 45 ? angl

Question

A tennis ball of mass 6.0?10?2kg and speed 29m/s strikes a wall at a 45 ? angle and rebounds with the same speed at 45 ?.

A) What is the magnitude of the impulse given to the ball?

p = ___________ kg*m/s

B) What is the direction of the impulse given to the ball?

_____ The given impulse is directed horizontally toward the wall.

or

_____ The given impulse is directed horizontally away from the wall.

A tennis ball of mass 6.0½10^?2kg and speed 29m/s strikes a wall at a 45 ? angle and rebounds with the same speed at 45 ?. A) What is the magnitude of the impulse given to the ball? p = ___________ kg*m/s B) What is the direction of the impulse given to the ball? _____ The given impulse is directed horizontally toward the wall. or _____ The given impulse is directed horizontally away from the wall.

Explanation / Answer

a) What is the magnitude?
A: Along x-direction,
Jx = 0.06(29Cos45)-(-0.06(29Cos45)) = 2.46 Kgm/s
Along y-direction,
Jx = 0.06(29Sin45)-(-0.06(29Sin45)) = 2.46 Kgm/s

b) 45 degree angle downward

tennis ball mass is not mentioned clearly...please put the value..as i am seeing 6 * 10 ^-2=.0.06 kg.so i am using the value

Since the ball rebounded from the wall at the same speed and the same 45 degrees angle, thus the magnitude of the impluse is given by:

I = F ?t = mv = (0.06)(29) = 1.74 kg m/s

Assuming that the wall is on the right, and the ball incidents the wall while moving to the right at 45 degrees angle, then the direction of the impulse imparted to the ball is to the left at also 45 degrees angle.

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