4. A thermos bottle contains 250g of coffee at 90 degrees C.To this is added 20g

Question

4. A thermos bottle contains 250g of coffee at 90 degrees C.To this is added 20g of milk at 5degrees C. After equilibrium isestablished, what is the temperature of the liquid? Assume no heatis lost to the thermos. show me all work and Answers so I can check it! 4. A thermos bottle contains 250g of coffee at 90 degrees C.To this is added 20g of milk at 5degrees C. After equilibrium isestablished, what is the temperature of the liquid? Assume no heatis lost to the thermos. show me all work and Answers so I can check it! show me all work and Answers so I can check it!

Explanation / Answer

Heat lost by coffee = heat taken by milk             m c dt = M C dt ' where Specific heat of milk C = 3890 J / kg o C           mass ofcoffee m = 250 g          mass ofmilk M = 20 g          dt = 90 -T          dt ' = T -5           C =specific heat of coffee = 1674000 J / kg o C substitue values weget final resultinmgtemperature T value

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