A massless spring with force constant 536 N/m is fastened at itsleft end to a ve

Question

A massless spring with force constant 536 N/m is fastened at itsleft end to a vertical wall. the acceleration of gravity is 9.8m/s2 . Initially,the 6 kg block and 3 kg block rest
on a horizontal surface with the 6 kg block in
contact with the spring (but not compressing
it) and with the 3 kg block in contact with the
6 kg block. The 6 kg block is then moved to
the left, compressing the spring a distance of
0.4 m, and held in place while the 3 kg block
remains at rest as shown below. The 6 kg block is then released andaccelerates to the right, toward the 3 kg block. The
surface is rough and the coefficient of friction
between each block and the surface is 0.4 . The
two blocks collide, stick together, and move
to the right. Remember that the spring is not
attached to the 6 kg block.
Find the speed of the 6 kg block just before
it collides with the 3 kg block. Answer in
units of m/s.

Explanation / Answer

let k be the spring constant , on compresseing the spring to a length x , the potentialenergy developed in the spring                 U = kx^2 / 2        the kinetic energy of themass that is pulled by the spring                 mv^2 /2 = kx^2 / 2                 v = (kx^2 / m)             ' v ' is the velocity of the 6kg mass just before hitting the3kg mass . plugging in the knwon values we can sovle for ' v '.                   

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