A rock of mass 37 kg accidentallybreaks loose from the edge of a cliff and falls

Question

A rock of mass 37 kg accidentallybreaks loose from the edge of a cliff and falls straight down. Themagnitude of the air resistance that opposes its downward motion is231 N. What is the magnitude of theacceleration of the rock?
I drew the free body diagram but lost from that point on. A rock of mass 37 kg accidentallybreaks loose from the edge of a cliff and falls straight down. Themagnitude of the air resistance that opposes its downward motion is231 N. What is the magnitude of theacceleration of the rock?
I drew the free body diagram but lost from that point on.

Explanation / Answer

F = mg = 37 kg x -9.8 m/s^2 = -362.6 N Air resistance force = 231 N Resulting foce: -362.6 N + 231 = -131.6 N F = ma a = F/m = -131.6 / 37 = -3.56 m/s2 (downward)

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