A rock is thrown down with an initial velocity of 10.5 m/s from the Verrazano Na

Question

A rock is thrown down with an initial velocity of 10.5 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70 m above water. Take upwards to be the positive direction.

a) Calculate the displacement at a time of 1.0 s.

b) Calculate the velocity at a time of 1.0 s

c) Calculate the displacement at a time of 1.5 s.

d) Calculate the velocity at a time of 1.5 s

e) Calculate the displacement at a time of 2.0 s.

f) Calculate the velocity at a time of 2.0 s

g) Calculate the displacement at a time of 2.5 s.

h) Calculate the velocity at a time of 2.5 s

Explanation / Answer

Initial velocity, u = 10.5m/s
a) Displacement at t = 1s
s = -ut - g * t * t /2 = -10.5 * 1 - 9.8*1*1/2 = -10.5-4.9 = -15.4m

b) Velocity at t = 1s
v=-u-gt = -10.5 - 9.8*1 = -20.3m/s

c) Displacement at t = 1.5s
s = -ut - g * t * t /2 = -10.5 * 1.5 - 9.8*1.5*1.5/2 = -15.75`-11.025 = -26.775m

d) Velocity at t = 1.5s
v=-u-gt = -10.5 - 9.8*1.5 = -25.2m/s

e) Displacement at t = 2s
s = -ut - g * t * t /2 = -10.5 * 2 - 9.8*2*2/2 = -20.1-19.6 = -39.7m

f) Velocity at t = 2s
v=-u-gt = -10.5 - 9.8*2 = -30.1m/s

g) Displacement at t = 2.5s
s = -ut - g * t * t /2 = -10.5 * 2.5 - 9.8*2.5*2.5/2 = -26.25-30.625 = -56.875m

h) Velocity at t = 2.5s

v=-u-gt = -10.5 - 9.8*2.5 = -35m/s

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