A) The current in a 47- resistoris 0.12 A. This resistor is in series with a 28-

Question

A)     The current in a 47- resistoris 0.12 A. This resistor is in series with a 28-resistor, and the series combination is connected across abattery. What is the battery voltage? B)      What resistance must beplaced in parallel with a 155- resistor to make theequivalent resistance 115 ? Please help! I don't get this at all. I will rate youlifesaver immediately! A)     The current in a 47- resistoris 0.12 A. This resistor is in series with a 28-resistor, and the series combination is connected across abattery. What is the battery voltage? B)      What resistance must beplaced in parallel with a 155- resistor to make theequivalent resistance 115 ? Please help! I don't get this at all. I will rate youlifesaver immediately!

Explanation / Answer

A)The current in a 47- resistor is 0.12 A. The 47- resistor is in series with a 28-resistor.Therefore,the total resistance of the two series resistorsis R = R1 + R2 or R = 47 + 28 = 75- The battery voltage is V = I * R Here,I = 0.12 A or V = 0.12 * 75 = 9 V B)Let the resistor that should be placed in parallel with a155- resistor to make the equivalent resistance 115 beR.Therefore,we get (1/R) + (1/155) = (1/115) or (1/R) = (1/115) - (1/155) = (8/3565) or R = (3565/8) = 445.625- or R = 47 + 28 = 75- The battery voltage is V = I * R Here,I = 0.12 A or V = 0.12 * 75 = 9 V B)Let the resistor that should be placed in parallel with a155- resistor to make the equivalent resistance 115 beR.Therefore,we get (1/R) + (1/155) = (1/115) or (1/R) = (1/115) - (1/155) = (8/3565) or R = (3565/8) = 445.625-

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.