A) Someone shoots a ping pong ball up into the air with a spring loaded toy gun.

Question

A) Someone shoots a ping pong ball up into the air with a spring loaded toy gun. It rises to a maximum height y1 before falling back down. Then he tilts it so that it is 60 degrees above the horizontal direction, and shoots it again. Assume that the ball exits the toy at the same speed in both cases, and that we can ignore air resistance.

What is the ratio of y2/y1?

B) What if I again shoot the same ping pong ball at an angle of 60 degrees, but now I increase the compression of the spring by 50%. What does my answer to part a get multiplied by?

Explanation / Answer

A) ( v^2cos heta = 2gh ) y2/y1 = 1/4 B) 2.25

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