The system shown in the figure is in equilibrium. A 15 kg mass in on the table.

Question

The system shown in the figure is in equilibrium. A 15 kg mass in on the table. A string attached to the knot and the ceiling makes an angle of 54 degrees with the horizontal. The system shown in the figure is in equilibrium. A 15 kg mass in on the table. A string attached to the knot and the ceiling makes an angle of 54 degrees with the horizontal. 017 10.0 points The system shown in the figure is in equilib- rium. A 15 kg mass is on the table. A string attached to the knot and the ceiling makes an angle of 54° with the horizontal. The coeff cient of the static friction between the 15 kg mass and the surface on which it rests is 0.33.

Explanation / Answer

here,

m1 = 15 kg

theta = 54 degree

u = 0.33

let the tension in the string be T

equating the force horizontally

u * m1 * g = T * cos(theta)

0.33 * 15 * 9.81 = T * cos(54)

solving for T

T = 82.6 N

equating the forces vertically

m * g = T * sin(theta)

m * 9.81 = 82.6 * sin(54)

solving for m

m = 6.81 kg

the hanging mass m is 6.81 kg

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.