1. 0/1 points I Previous Answers SerCP11 18.P.001 My Notes Ask Your Teacher A ba

Question

1. 0/1 points I Previous Answers SerCP11 18.P.001 My Notes Ask Your Teacher A battery having an emf of 9.46 V delivers 119 mA when connected to a 68.0 2 load. Determine the internal resistance of the battery. 32.87 Your response differs from the correct answer by more than 100%. Need Help? Read It 2. 44 points SerCP11 18.P.006. My Notes Ask Your Teacher Three 2.2 2 resistors are connected in series with a 21.0 V battery. Find the following (a) the equivalent resistance of the circuit (b) the current in each resistor (c) Repeat for the case in which all three resistors are connected in parallel across the battery. equivalent resistance current in each resistor Need Help?Read

Explanation / Answer

1.

E = emf of the battery = 9.46 Volts

R = load resistance = 68 ohm

r = internal resistance = ?

i = current coming from battery = 119 mA = 0.119 A

Using ohm's law

i = E/(R + r)

0.119 = 9.46/(68 + r)

r = 11.5 ohm

2.

a)

the equivalent resistance of three resistors in series is simply the sum of their indivisual resistances. hence

Req = 2.2 + 2.2 + 2.2

Req = 6.6 ohm

b)

i = current in each resistor (since in series, same current flows through each resistor)

E = battery Emf = 21 Volts

Using ohm's law

i = E/Req

i = 21/6.6

i = 3.2 A

c)

equivalent resistance in parallel is given as

1/Req = 1/2.2 + 1/2.2 + 1/2.2

Req = 0.73 ohm

i = current in each resistor

E = battery Voltage = Voltage across each resistor (In parallel , Voltage remain same)

Using ohm's law

i = E/2.2

i = 21/2.2

i = 9.6 A

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