1. 0/2 points ! Prvious Answors OSCalPhys1 3.P060.VHA My Notos Ask Your A passen

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1. 0/2 points ! Prvious Answors OSCalPhys1 3.P060.VHA My Notos Ask Your A passenger on a moving train walks at a speed of 2.20 m/s due north relative to the train. The passenger's speed with respect to the ground is 4.5 m/s at an angle of 31.0° west of north. What are the magnitude and direction of the velocity of the train relative to the ground? 5.67 Think about the position vectors of the train (an arbitrary fixed point on it) and the passenger with respect to a fixed origin on the ground. What is the position vector of the passenger with respect to the train? How is it related to their positions with respect to the origin? Since velocity is position per unit time, what is the relationship between the relative velocity of the passenger with respect to the train and the velocities with respect to the origin? m/s magnitude direction west or north Supporting Materials Physical Constants Submit Answer Save Progress

Explanation / Answer

Here ,

velocity of pessener relative to train is

vpt = 2.2 j m/s

vp = 4.5 * (- sin(31 degree) i + j * cos(31 degree))

vp = -2.32 i + 3.86 j

let the velocity of train is vt

vpt = vp - vt

2.2 j = -2.32 i + 3.86 j - vt

vt = -2.32 i + 1.66 j

vt = sqrt(2.32^2 + 1.66^2) at arctan(2.32/1.66)

vt = 2.83 m/s at 54.4 degree west of north

the velocity of train is 2.83 m/s at 54.4 degree west of north

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