A 5.00 m long rigid beam with a mass of 100.0 kg is supported ateach end. An 80.

Question

A 5.00 m long rigid beam with a mass of 100.0 kg is supported ateach end. An 80.0 kg worker stands on the beam, 4.00 m from theleft support. 30.0 kg of brick are stacked on the beam 1.50 m fromthe left end of the beam. How much upward force does each supportexert on the beam? Be specific by left support and rightsupport?

Okay so i've been working on this problem for a good while now andi just cannot seem to get the correct answer. Everything thati've tried turns out to be wrong. Can you guys tell me whatim doing wrong?

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Explanation / Answer

so    = (100*9.8)(2.5m) + 80*9.8*4 +30*9.8*1.5+FR (5) = 0   Therefore FR = [ 2450+ 3136 + 441 ]/5       = 1205.4 N
  From net force    FR +FL = W + WW + WB       FL  =   (W +WW + WB )/  FR = (100 + 80 + 30 )9.8 -(1205.4 ) = 852.7 N       FL  =   (W +WW + WB )/  FR = (100 + 80 + 30 )9.8 -(1205.4 ) = 852.7 N

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