A 5.0-A current runs through a 10-turn (0.12 m) 2 -area coil. The coil is in a 0

Question

A 5.0-A current runs through a 10-turn (0.12 m) 2 -area coil. The coil is in a 0.14-T magnetic field.
Conside the three possibilities in (Figure 1)

A) What is the direction of the torque on the loop in case a?

B) Determine the magnitude of the torque exerted on the coil in case a.   

C) What is the direction of the torque on the loop in case b?

D) Determine the magnitude of the torque exerted on the coil in case b.

E) Determine the magnitude of the torque exerted on the coil in case c.

F) What is the direction of the torque on the coil shown in the figure (case c)?

Can you explain how to find the direction of torque? (using the right hand rule)

Explanation / Answer

= NIABsin
(A)
Force on the Right side of loop is Vertically Downwards, while Force on the Left side of loop is Vertically Upwards.
Net Direction of torque = Clockwise;

(B)
= NIABsin
Substituing Values,
t = 10*5.0*0.12*0.14*sin(90)
t = 0.84 Nm

(c)
The force will be parallel to the coil.
So No Net Torque exists.

(D)
Magnitude of the torque exerted on the coil in case b = 0

p.s:- We calculate Direction of Force on the Coil using right hand rule, Not torque.

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