I am confused over a step in the Cramster solution key, it isthe 4th line of the

Question

I am confused over a step in the Cramster solution key, it isthe 4th line of the 4th step where 2 pi turns into 4 pi and Ibecomes 2I. The question reads: Four long, parallelconductors carry equal currents of I=5A. The currentdirection is into the page at points A and B (indicated by crosses)and out of the page at Cand D (indicted by dots). Calculatethe magnitude and direction of the magnetic field at point P ,which is located int he center of the square, with sides of .200m The diagram is shown in the cramster solution key Thanks. I am confused over a step in the Cramster solution key, it isthe 4th line of the 4th step where 2 pi turns into 4 pi and Ibecomes 2I. The question reads: Four long, parallelconductors carry equal currents of I=5A. The currentdirection is into the page at points A and B (indicated by crosses)and out of the page at Cand D (indicted by dots). Calculatethe magnitude and direction of the magnetic field at point P ,which is located int he center of the square, with sides of .200m The diagram is shown in the cramster solution key Thanks.

Explanation / Answer

   here we must recollect that the conductors thatA and B (indicated by the crosses) and

   out of the
   page at C and D (indicated by thedots)
   the distance from each wire to point P will be
   r = (1 / 2) [(0.200 m)2 + (0.200m)2]
     = ......... m
   now at the point P the magnitude of the magnetic fieldproduced by each of the wire

   will be
   B = o I / 2 r
      = ........ T
   the net field will be
   Bnet = 4 (B) sin45.0o
           =........ T towards bottom of the page

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