A 170-g hockey puck sliding on ice perpendicularly impacts aflat piece of sidebo

Question

A 170-g hockey puck sliding on ice perpendicularly impacts aflat piece of sideboard. Its incoming momentum is 5.90 kg*m/s.It rebounds along its incoming path after having suffered amomentum change (magnitude) of 9.00 kg*m/s. A.If the impact with the board took36.0 ms, determine the magnitude of the average force exertedby the puck on the board. B.Determine the direction of the averageforce exerted by the puck on the board. opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct C. Determine the magnitude of the the finalmomentum of the puck. D. Determine the direction of the finalmomentum of the puck. opposite direction as the incomingmomentum same direction as the incoming momentum Correct D. Determine the direction of the finalmomentum of the puck. opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct opposite direction as the incomingmomentum same direction as the incoming momentum Correct E.Was this collision elastic orinelastic? elastic inelastic Correct F.Prove your answer mathematically. E.Was this collision elastic orinelastic? elastic inelastic Correct F.Prove your answer mathematically. elastic inelastic Correct F.Prove your answer mathematically. elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct elastic inelastic Correct opposite direction as the incoming puck’svelocity same direction as the incoming puck’svelocity Correct A 170-g hockey puck sliding on ice perpendicularly impacts aflat piece of sideboard. Its incoming momentum is 5.90 kg*m/s.It rebounds along its incoming path after having suffered amomentum change (magnitude) of 9.00 kg*m/s. A.If the impact with the board took36.0 ms, determine the magnitude of the average force exertedby the puck on the board. B.Determine the direction of the averageforce exerted by the puck on the board. C. Determine the magnitude of the the finalmomentum of the puck. p =3.10 {rm kg . m/s} Correct D. Determine the direction of the finalmomentum of the puck. E.Was this collision elastic orinelastic? F.Prove your answer mathematically.

Explanation / Answer

Given : .                         Initial momentum is : P1 = 5.90 kg - m /s .                         Momentum change is : P = 9.00 kg - m/s .                          Hence P = P2 - (-P1 ) ==> P2 = 9.00  - 5.90 =  3.10 kg -m/s . (a)    Average force exerted is : .                     F   = P / t    = 9.00 /(36 * 10-3 )   =   ----------- N . (b)   same direction as the incoming puck’svelocity . (c)   Final momentum is:    P2  =  3.10 kg -m/s . (d)   opposite direction as the incomingmomentum . (e)   collision is : inelastic . Hope this helps u!

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