For this section we use Snell\'s law, but I\'m not seeinghow to apply it. Questi

Question

For this section we use Snell's law, but I'm not seeinghow to apply it. Question: Suppose you look through a 3.3 mm thick window comprised of a material whoserefractive index is 1.63. (a) By whattime interval is the light you see delayed by having to go throughglass instead of air? (answershould be in seconds) (b) By howmany wavelengths is it delayed, if its vacuum wavelength is 600nm? (answershould be in wavelengths)

For this section we use Snell's law, but I'm not seeinghow to apply it. (a) By whattime interval is the light you see delayed by having to go throughglass instead of air? (answershould be in seconds) (b) By howmany wavelengths is it delayed, if its vacuum wavelength is 600nm? (answershould be in wavelengths)

Explanation / Answer

(a)     the index of refraction is defined by theratio     n = c / v     where c is the speed of light in vacuum and v isthe speed of light in the medium     through the glass we get     1.63 = (3.0 x 108 m / s) / (3.3 x10-3 m / t)     t1 = ....... s     through the air we get     1.00 = (3.0 x 108 m / s) / (3.3 x10-3 m / t)     t2 = ....... s     so the time delayed will be     t = t1 - t2       = ......... s (b)     we know that     n = / n     where is the vacuum wavelength andn is the wavelength in the medium     1.63 = 600 nm /n    n =........ nm

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