Figure 10-38 shows an arrangement of 15 identical disks that havebeen glued toge
ID: 1725707 • Letter: F
Question
Figure 10-38 shows an arrangement of 15 identical disks that havebeen glued together in a rod-like shape oflength L = 1.4200 m and (total)mass M = 146.0 mg. The arrangement can rotateabout a perpendicular axis through its central disk atpoint O. (a) What is therotational inertia of the arrangement about that axis? Give youranswer to four significantfigures. (b) If we approximated thearrangement as being a uniform rod of mass M andlength L, what percentage error would we make inusing the formula in Table 10-2e to calculate therotational inertia?
Fig. 10-38
Explanation / Answer
x.
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