A bullet of mass 0.0024 kg moving at 530 m/s impacts a large fixed block of wood
ID: 1725304 • Letter: A
Question
A bullet of mass 0.0024 kg moving at 530 m/s impacts a large fixed block of wood and travels 6.7 cm before coming to rest. Assuming that the acceleration of the bullet is constant, find the force exerted by the wood on the bullet. Answer in units of kN. A bullet of mass 0.0024 kg moving at 530 m/s impacts a large fixed block of wood and travels 6.7 cm before coming to rest. Assuming that the acceleration of the bullet is constant, find the force exerted by the wood on the bullet. Answer in units of kN.Explanation / Answer
Given that the mass of bullet is m = 0.0024 kg
Initial velocity is u = 530 m/s
final velocity is v = 0 m/s
Distance traveled before coming to rest is d = 6.7 cm = 0.067m
---------------------------------------------------------------
From the equation of motion acceleration is a = (v2 - u2 ) / 2d
= ( 0 -u2 )/ 2d
= -2096268.65 m/s2
Then the force is F =ma
= 5031.04 N
= 5.031 kN
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.