A bullet of mass .2 kg moving horizontaly at 450 m/s hits a 3kg block that is at

Question

A bullet of mass .2 kg moving horizontaly at 450 m/s hits a 3kg block that is at rest on a frictionless table.

a) after emerging from the block the bullet is traveling 330 m/s. What is the speed of the block and momentum after impact

b)repeat question a) only now assume the bullet bounces back at 330m/s. What is the final speed of the block and the total momentum after impact?

c)Repeate the above questions only now the bullet sticks to the block. What is the final speed of the block and total momentum.

Explanation / Answer

a) conservation of momentum

.2*450 = 3*v + .2*330

v=8

b) now .2*450 = 3*v - .2*330

v=52 m/s

c) now .2*450 = 3.2*v

v=28.13 m/s

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