A bullet of mass 0.007 kg and initial speed 440.0 m/s penetrates an initially st

Question

A bullet of mass 0.007 kg and initial speed 440.0 m/s penetrates an initially stationary wooden block with a of mass 0.59 kg and lodges in it.

1) What is the initial velocity of the center of mass of the bullet-block system before the collision

2) What is the velocity of the block (with the embedded bullet) after the collision?

3) How much mechanical energy was lost during the collision? (This mechanical energy was transformed into sound and friction generated heat.)

4) Now lets say that instead of being embedded in the block, the bullet comes out the other side of the block with a velocity of 326.0 m/sec. Assuming the block remains intact, what is its velocity after the collision?

Explanation / Answer

a)Ucm= mv/(m+M)=5.16 b)Vb= mv/(m+M)=5.16 c)Wl=.5*(M+m)*v^2 - .5*m*u^2=-676 so lost=676 J d)mu=Mv +mv' so v=.88 m/s

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