The torque is t = r ´ F . In the problem F = (3, 2 ,0), i.e. F x =3, F y = 2, F

Question

The torque ist=r´F.
In the problem F = (3, 2 ,0), i.e. Fx =3, Fy = 2, Fz = 0.
The lever arm is the vector pointing from the axis of rotation atr’ = (-2, 1, 0) to the point where the forceis applied at r = (1, 3, 0). This vector isgiven by r – r’ = (3,2, 0).
Here r – r’ isparallel to F, the torque therefore is zero.

In general:
If you have the components of two vectors A andB. you can always find the components of the crossproductC=A´B interms of the components of A andB.

Cx=AyBz-AzBy
Cy=AzBx-AxBz
Cz=AxBy-AyBx

Explanation / Answer

Torque = rxF               = ( 3i + 2j) x ( 3i +2j )              = 6k - 6k = 0 Nm

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