A compact disc (CD) stores music in a coded pattern of tinypits 10 -7 m deep. Th

Question

A compact disc (CD) stores music in a coded pattern of tinypits 10-7 m deep. The pits are arranged in a track thatspirals outward toward the rim of the disc; suppose the inner andouter radii of this spiral are 26.0 mm and52.0 mm, respectively. As the disc spinsinside a CD player, the track is scanned at a constantlinear speed of 1.19 m/s. innermost = 1 rad/s outermost = 2 rad/s
(c) What is the average angular acceleration of a maximum-durationCD during its 71.0-min playing time? Takethe direction of rotation of the disc to be positive.
rad/s2 A compact disc (CD) stores music in a coded pattern of tinypits 10-7 m deep. The pits are arranged in a track thatspirals outward toward the rim of the disc; suppose the inner andouter radii of this spiral are 26.0 mm and52.0 mm, respectively. As the disc spinsinside a CD player, the track is scanned at a constantlinear speed of 1.19 m/s. innermost = 1 rad/s outermost = 2 rad/s
(c) What is the average angular acceleration of a maximum-durationCD during its 71.0-min playing time? Takethe direction of rotation of the disc to be positive.
rad/s2 innermost = 1 rad/s outermost = 2 rad/s

Explanation / Answer

(_innermost) = v/(R_innermost) = (1.19)/(26.0e-3) = 45.769rad/sec (_outermost) = v/(R_outermost) = (1.19)/(52.0e-3) = 22.885rad/sec Item#C: {Average Angular Acceleration} = (_bar) =      = /t      = ((_outermost) - (_innermost))/t      = ((22.885) -(45.769))/((71.0)*(60))      = -0.005372 rad/sec^2 .

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.