A baseball player is trying to stretch a double into a triple. The62.0-kg player

Question

A baseball player is trying to stretch a double into a triple. The62.0-kg player begins sliding 3.00 m fromthird base with a speed of 4.23 m/s. (a) If the player comes to rest at third base,how much work was done on the player by friction?
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(b) What was the coefficient of kinetic friction between the playerand the ground?
(a) If the player comes to rest at third base,how much work was done on the player by friction?
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(b) What was the coefficient of kinetic friction between the playerand the ground?

Explanation / Answer

Gvien           mass ofthe player   m = 62 kg             distance s = 3 m            initial velocity   u = 4.23 m/s            final velocity    v = 0 m/s                   v2-u2 = 2as                         a = - u2 / 2s                             = 2.98 m/s2           Force F = ma                             = 62 x 2.98                           =184.89 N            work = F S                     = 184.89 x 3                      = 554.67 J             coefficientof kinetic friction   k = a / g                                                               = 2.98 / 9.8                                                                 = 0.304                       

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