A baseball leaves a pitcher\'s hand horizontally at a speed of 117 km/h. The dis

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A baseball leaves a pitcher's hand horizontally at a speed of 117 km/h. The distance to the batter is 18.3 m. Neglect air resistance. (please write the steps and equations used clearly)

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Explanation / Answer

(A) v0x = v0 = 117 km/h = 117 x 1000 m / 3600 s

v0x = v0 = 32.5 m/s

in horizontal, d =v0x t

t1 = (18.3/2)/32.5 = 0.28 sec  

(B) t2 =(18.3 /2) / 32.5 = 0.28 sec

(C) y1 = v0y t + ay t^2 /2 = 0 + 9.8 x 0.28^2 /2

y1 = 0.38 m

(D) after 0.28 s, vy = v0y + ayt

vy = 0 + (0.28 x 9.8 ) = 2.74 m/s

y2 = (2.74 x 0.28) + (9.8 x 0.28^2 /2)

y2 = 1.15 m

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