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A) What is the speed (in meters/second) at which thePluto goes around the Sun? B

ID: 1723073 • Letter: A

Question

A) What is the speed (in meters/second) at which thePluto goes around the Sun? B) How does the Pluto's cetripetal acceleration in orbitabout the Sun compare to the acceleration of objects near thesurface of the Earth? C) What is the magnitude of the force that the Sun'sgravity exerts on the Pluto to keep it in orbit? D) According to Newton's third law, all forces occurin pairs. What is the reaction force to the Sun'sgravity on the Pluto? Explain. A) What is the speed (in meters/second) at which thePluto goes around the Sun? B) How does the Pluto's cetripetal acceleration in orbitabout the Sun compare to the acceleration of objects near thesurface of the Earth? C) What is the magnitude of the force that the Sun'sgravity exerts on the Pluto to keep it in orbit? D) According to Newton's third law, all forces occurin pairs. What is the reaction force to the Sun'sgravity on the Pluto? Explain.

Explanation / Answer

Ok let's get down to business
so your radius of Pluto r= 5.91 X 10^12 m Period of the time to make one revolution around sun T=7.84 X 10^9 sec PART A) Acc=v^2/r T=2*pi*r/v v=2*pi*r/T PLUG IN THE ABOVE VALUES OF R AND T v=2*pi*(r)/T v should equal=4736.432 m/s
PART B) Acc= v^2/r Acc(centripetalacceleration)=(4736.432m/s)^2/(5.91X10^12m)
PART C) mass sun(Ms)=1.987 X 10 ^30 kg mass pluto(m)=1.27 X 10^22 kg universal Gravitation constant (G) = 6.67 X 10^-11N*m^2/kg^2 distance from sun to pluto (r)= 5900 X 10^6 km F= GMsm/(r^2) =plug in your values and get force which should equal 2.939 X10^32 N
PART D) An electromagnetic force is being exerted on Pluto bythe sun. At the same time pluto exerts gravitational force.
hope this helps, if not i guess i'll just have to jump offlawrenson.
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