A point charge moving in a magnetic field of 1.27 Teslaexperiences a force of 0.

Question

A point charge moving in a magnetic field of 1.27 Teslaexperiences a force of 0.732E-11 N. The velocity of the charge isperpendicular to the magnetic field.
6. [1pt]
In this problem, we use the points of the compass and `into' and`out of' to indicate directions with respect to the page. If themagnetic field points south and the force points out of the page,then give all possible correct answers for the charge Q. (Give allcorrect statments in alphabetical order: ACD, BE, etc.)

A) Q is positive, moving east
B) Q is negative, moving west
C) Q is positive, moving west
D) Q is negative, moving east
E) Q is negative, moving north

Explanation / Answer

      Force,F = q ( V X B) Here, F= Force                      q = Charge                       V = Force                       B = Magneticfield                ( Note: BOLD letters indicate vector)     Right Hand Rule ( R H R ) :                      Force ( F ) - Palm                      Magnetic field ( B ) - Fingers                      Velocity of positive charge ( V ) -Thumb     Ans:    Options: (C) - - Q is positive, moving west         and       (D) - - Q is negative,moving east

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