A point charge moving in a magnetic field of 1.30 Tesla experiences a force of 0
ID: 1508982 • Letter: A
Question
A point charge moving in a magnetic field of 1.30 Tesla experiences a force of 0.853E-11 N. The velocity of the charge is perpendicular to the magnetic field.
8. [10pt]
In this problem, we use the points of the compass and `into' and `out of' to indicate directions with respect to the page. If the magnetic field points west and the force points out of the page, then give ALL possible correct answers for the charge Q (i.e., B, AC, BCD...).
A) Q is negative, moving east
B) Q is negative, moving south
C) Q is positive, moving north
D) Q is positive, moving south
E) Q is negative, moving north
Answer:
9. [10pt]
The speed of the charge is 0.410E8 m/s. Calculate the magnitude of the charge.
Answer:
10. [10pt]
The path of the charge in the magnetic field is a circle. Assume that the charge is positive and has a mass of 1.673E-27kg, the mass of a proton. What is the radius of the circle?
Answer:
Answer:
Explanation / Answer
in first
B) Q is negative, moving south
C) Q is positive, moving north
part2
F =q*VXB
F = qVB
q = F/VB = 0.853*10^-11 / ( 0.410*10^8* 1.30 )
q = 1.6*10^-19 C
r =mV/qB
= 1.673*10^-27 *0.41*10^8 / ( 1.6*10^-19 *1.3)
= 0.329 m ....... radius
correct answers are
A) The force on the short wire due to the long wire is toward the right.
C) The magnetic field of the long wire points out of the paper at the location of the short wire.
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