A point charge -2.06nC is at the point x = 0.60 m, y = 0.80 m , and a second poi

Question

A point charge -2.06nC is at the point  x = 0.60 m, y = 0.80 m , and a second point charge  5.57nC is at the point  x = 0.60 m , y = 0.ONLY NEED HELP WITH PART D THE OTHER ANSWERS ARE PROVIDED FOR REFERENCE.

What is the magnitude of the electric field set up at the origin from q1?

18.5

(ANSWER)

What is the magnitude of the electric field set up at the origin from q2?

139

(ANSWER)

What is the x component of the net electric field at the origin?

-128

ANSWER

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Correct

Part D

What is the y component of the net electric field at the origin?

14.8

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Correct

Part E

Calculate the magnitude of the net electric field at the origin due to these two point charges.

129

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Correct

Part F

Calculate the direction of the net electric field at the origin due to these two point charges.

????

18.5

Explanation / Answer

let

q1=5.57 nC

q2=-2.06 nC

now,

E1=kq1/r1^2

=(9*10^9*5.57*10^-9)/(0.6)^2

=139.25 N/C

and

E2=kq2/r2^2

here r2^2=0.6^2+0.8^2 =1 m

=(9*10^9*2.06*10^-9)/1

=18.54 N/C

here

E1 has only X-component it does not have any Y-component

E1=(E1x)i+(E1y)j

=(139.25)i+(0)j

and

E2=(E2x)i+(E2y)j

=(E2*cos(theta)i+(E2*sin(theta))j

here

cos(theta)=0.6/1

====> theta=53.12

now

E2=(18.5*cos(53.13)i+(18.5*sin(53.13))j

E2=(11.1)i+(14.83)j

now Y-component of Enet is,

Ey=(0+14.83)

Ey=14.83 N/C ........is answer

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