Specific enthalpy of superheated system at the pipe inlet h1=3172.63 kJ/kg and a

Question

Specific enthalpy of superheated system at the pipe inlet h1=3172.63 kJ/kg and at the outlet h2=3172.93 kJ/kg

A certain horizontal pipe carries steam at an inlet pressure of P_1 = 265 kPa and temperature T_1 = 350 degree C. Some distance from the entrance, the steam is observed to have a pressure of P_2 = 250 kPa, while T_2 is unchanged. Calculate the work done in this process (you will commonly hear this referred to as "flow work"), using the usual convention that work done by the system is positive. Explain the nature and origin of this work. What is the underlying physical mechanism at work in this process?

Explanation / Answer

solution

workdone by the process = enthalpy difference between inlet and outlet of the pipe

= h2 - h1

= 3172.93 - 3172.63

= 0.30 KJ / Kg

= 300 J / Kg

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.