Problens 4.15(GO Tutorial) resp For an alloy that consists of 6 at% Zn and 94 at

Question

Problens 4.15(GO Tutorial) resp For an alloy that consists of 6 at% Zn and 94 at% Cu, what are the concentrations of a) Zn and (b) da in weight percent? The atomic weights of Zn and Cu are 65.39 and 63.54 amo wt% wt% Click if you would like to Show Work for this question: gen Shon Work By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Coprshi e 2000-2016br lehn Wiley & Sons, ine, o related comparses. A rights reserved. Desktop Address

Explanation / Answer

Atomic weight of Fe is 65.39
Atomic weight of Cu is 63.54
Avogadro's Number is 6.022 x 1023

Consider a sample containing 100 atoms. So a sample of 6 at% of Zn and 94 at% of Cu would contain 6 Zinc atoms and 94 Copper atoms.

Weight of 6 Zn atoms
= 6 x atomic weight of Zn / Avogadro's Constant
= 6.515atomic mass units

Weight of 75 Cu atoms
= 75 x atomic weight of Cu / Avogadro's Constant
= 79.135 atomic mass units

Therefore, wt% of Zinc
= Zn weight x 100% / (total weight of Zn + Cu atoms)
= 6.515 x 100 / (6.515+79.135)

= 7.61%

wt% of Cu
= Cu weight x 100% / (total weight of Zn + Cu atoms)
= 79.135 x 100 / (6.515+79.135)

=92.39

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