Problems30 x oard.com/bbcswebdav/pid-1489406-dt-content-rid-14147710 1/cour rida
ID: 396831 • Letter: P
Question
Problems30 x oard.com/bbcswebdav/pid-1489406-dt-content-rid-14147710 1/cour riday Specik G Internship MGSC 303-01 201910/ n16.6 Sampling 4 pieces of precision-cut wire (to be used in a computer assembly) every hour for the past 24 hours has produced the following results: toHour ne to Hour 3.1185" 2.83 1.31 3.12 1.06 2.84 2.86 1.43 2.74 1.29 3.41 1.61 2.89 1.09 2.65 1.08 3.28 2.94 1.58 2.64 3.25" 71" 13 3.10 1.18 3.22 1.43 .39 1.26 3.07 1.17 2.86 3.05 2.65 1.13 3.02 2.85 2.83 1.17 2.97 14 15 16 17 .50 .53 19 20 ere 10 1.33 46 23 24 12 40 .97 ite" Develop appropriate control charts and determine whether there is ast any cause for concern in the cutting process. Plot the information and look Jor patterns. P ..Vs6.7 Auto pistons at Yongpin Zhou's plant in Shanchai t of BlackboardCollabo.. .msiExplanation / Answer
Problem: S6.7
Steps:
1. Calculate total of sample mean and range
2. calculate average of sample mean and range by dividing total with sample size
Day
Mean
Range
1
156.9
4.2
2
153.2
4.6
3
153.6
4.1
4
155.5
5
5
156.6
4.5
Total
775.8
22.4
Average
155.16
4.48
For sample size of n = 10, A2 = 0.31, D3 = 0.22 and D4 = 1.78
156.54, 153.78
UCLXbar = Xbar + (A2)(Rbar) = 155.16 + (0.31)(4.48) = 156.54
LCLXbar = Xbar - (A2)(Rbar) = 155.16 - (0.31)(4.48) = 153.78
UCLXbar = 156.54 and LCLXbar = 153.78
UCLR = (D4)(Rbar) = (1.78)(4.48) = 7.96
LCLXbar = (D3)(Rbar) = (0.22)(4.48) = 0.99
UCLR = 7.96 and LCLR = 0.99
a. Value of Xbar = overall mean = 155.16
b. Value of Rbar = 4.48
c. Control limits:
Xbar chart: UCLXbar = 156.54 and LCLXbar = 153.78
R chart: UCLR = 7.96 and LCLR = 0.99
(Note: Please include one question per post)
Day
Mean
Range
1
156.9
4.2
2
153.2
4.6
3
153.6
4.1
4
155.5
5
5
156.6
4.5
Total
775.8
22.4
Average
155.16
4.48
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