A 1 m^3 rigid tank has propane at 100 kPa and 300 K. The tank is connected to an
ID: 1718272 • Letter: A
Question
A 1 m^3 rigid tank has propane at 100 kPa and 300 K. The tank is connected to another 0.5 m3 rigid tank which has propane at 250 kPa and 400 K by a ball valve. The valve is opened and both tanks come to a uniform state at 325 K. Stale all assumptions you need to solve the problem. Calculate the final pressure of propane in both tanks? Calculate the mass of propane before and after opening the valve in each tank. Sketch the process on a P-V diagram. Find the compressibility factor of propane in each tank before opening the valve. Calculate the change in internal energy and enthalpy of propane in each tank.Explanation / Answer
1. we assumed the propane as an ideal gas
R as a constant R=8.31
M= 44,1 g/mol = 44.1 x10^-3 Kg / mol
2.
mass of first tank:
PV=m(R/M)T
m1= 100x10^3 x1 / ((8.31/44.1x10^-3)(300)) = 1.769 Kg
mass of the second tank:
m2= 250x10^3 x 0.5 / ((8.31/44.1x10^-3) (400)) = 1.658 Kg
so the preassure of the both tanks is
PV=m(R/M) T
P= (m/V) ( R/M) T = ( (1.658+1.769)/ 1.5) ( (8.31/44.1x10^-3) ) (325) = 139.916 kPa
3.
before
mass 1 = 1.769 Kg
mass 2 =1.658 Kg
total mass= 1.769+1.658= 3.427 Kg
4. Sorry I dont remember how to do this sketch
5. Z1=PV/ RT = 40.11
Z2= PV / RT = 37.6
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