A 1 275.0 kg car traveling initially with a speed of 25.000 m/s in an easterly d
ID: 1288984 • Letter: A
Question
A 1 275.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 8 300.0 kg truck moving in the same direction at 20.000 m/s. The velocity of the car right after the collision is 18.000 m/s to the east.
(a) What is the velocity of the truck right after the collision? (Give your answer to five significant figures.)
m/s east
21.07
(b) What is the change in mechanical energy of the car
Explanation / Answer
Conservation of momentum
1275 . 25 + 8300 . 20 = 1275 . 18 + 8300 . V
197875 = 22950 + 8300 V
V = 174925 / 8700 = 21.07 m/s ( speed of truck after collision )
b) energy before = 0.5 . 1275 . 25^2 + 0.5 . 8300 . 18^2 = 1743037.5 J
energy after = 0.5 . 1275 . 18^2 + 0.5 . 8300 . 21.07^2 = J 206550
Energy lost = 417706 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.