A 1 metre spring lies horizontally on a table. You hang it vertically on a holde

Question

A 1 metre spring lies horizontally on a table. You hang it vertically on a holder similar to the one you used in the simple pendulum experiment. Because of the mass of the spring itself it now extends to 1.1 m. You hang a holder of unknown mass and now it's 1.2 metres long. You decide to hang a 500 gram mass on the holder and now it's 1.3 metres long. What is the spring constant of the spring? A 1 metre spring lies horizontally on a table. You hang it vertically on a holder similar to the one you used in the simple pendulum experiment. Because of the mass of the spring itself it now extends to 1.1 m. You hang a holder of unknown mass and now it's 1.2 metres long. You decide to hang a 500 gram mass on the holder and now it's 1.3 metres long. What is the spring constant of the spring?

Explanation / Answer

since the force exerted by the spring is proportinal to its elongation....when we hang 500 gms of mass the change in its length is 0.1m(from 1.2 m to 1.3 m).let the spring constant be K

K*0.1=0.5*g

K=5*g

K=49.05 N/m

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