7:50 AM 55% D Locked SIM F blackboard indstate.edu A particle moves along a hori
ID: 1717246 • Letter: 7
Question
7:50 AM 55% D Locked SIM F blackboard indstate.edu A particle moves along a horizontal path with its velocity varying with time as shown. What is the average acceleration of the particle? Aparticle has an initial velocity of 30fts to the left. ltthen passes through the same location 5 seconds later with a velocity of 50fts to the right. What is the average velocity of the particle during the 5 second interval? Aparticle has an initial velocity of 3fts to the left at so 0f Determine its position when t 3s if the acceleration of the particie is 21ths to the A particle is moving with an initial velocity of 12tts and a constant acceleration of 3.78fts in the same direction as the velocity. Determine the distance that the particle has traveled when the velocity reachesExplanation / Answer
Ans
5)
initial velocity= 3 m/s at t=2s
final velocity= 5 m/s at t=7s
Avg acceleration= (final- initial)/(time difference)
= (5-3)/(7-2)
= 0.4 m/s2
it is positive therefore accleration is towards right.
6)
initial velocity= -30 ft/s (direction is left therefore negative)
final velocity= 80 ft/s
Avg acceleration= (final- initial)/(time difference)
= (50-(-30))/(5)
= 80/5
=1.6 ft/s2
it is positive therefore accleration is towards right.
7) initial velocity u = 3 ft/s
s0 at t=0 is zero
acceleration a = 2 ft/s^2
s at t=3s
using 2nd equation of motion
s = s0 ut + 0.5at^2
= 0+ 3 (3) + 0.5x 2x3x3
= 18 ft
tve therefore 18 ft to the right.
8) initial velocity u= 12 ft/s
acceleration a= 3.78 ft/s^2
final velocity v= 30 ft/s
using 3rd equation of motion
v^2 = u^2 + 2as
30x30 = 12x12 + 2x3.78xs
2x3.78xs = 756
s = 100 ft
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