During a seventh-inning stretch of a baseball game, groundkeepers drag mats acro

Question

During a seventh-inning stretch of a baseball game, groundkeepers drag mats across the infield dirt to smooth it. A groudskeeper is pulling a mat as a constant velocity by applying a force of 120 N at at angle of 22 degrees above the horizontal. the coefficient of kinetic friction between the mat and the ground is .60 Find the magnitude of the frictional force between the dirt and the mat, and the weight and the mat.

Here I tried to find teh weight of the mat by adding all the x-components, which I had as Applied Force-Frictional Force-x-component of MG+ the x-component of the Normal force.

I tried to find the Normal force by setting the x-components to zero and solving for N which gave me mg cos 22. to which I multiplied the coefficient of kinetic friction. I tried to add all the x-components together and solve for m and then multiply it by g to get the weight. I am obviously doing something wrong. Could you please help me to solve this problem for weight and magnitude going step by step? I am studying for a test.

Thanks!

Explanation / Answer

Applying the newton's 2nd law of motion, F - N -mgsin = ma F = N+mgsin    (since a=0 , constant speed) the frictional force f = F-mgsin

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.