During a pregame warmup period, two basketballs collide above the hoop when in t

Question

During a pregame warmup period, two basketballs collide above the hoop when in the positions shown. Just before impact, ball 1 has a velocity v1 which makes a 34° angle with the horizontal. If the velocity v2 of ball 2 just before impact has the same magnitude as v1, determine the two possible values of the angle (1 < 2) measured from the horizontal, which will cause ball 1 to go directly through the center of the basket. The coefficient of restitution is e = 0.64.

See picture at http://www.chegg.com/homework-help/questions-and-answers/pregame-warmup-period-two-basketballs-collide-hoop-positions-shown-impact-ball-1-velocity--q8489913?trackid=634a56b9&strackid=5adff604&ii=1

Explanation / Answer

e = Speed before collision/Speed after Collision

0.64 = V1/x

x = V1/0.64

Speed of sperartion = e*Speed of approch

= 0.64*1

= 0.64

Angle 1 = 34

Angle 2 = 56

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