A basketball star covers 2.80 m horizontally in a jump to dunk the ball. His mot

Question

A basketball star covers 2.80 m horizontally in a jump to dunk the ball. His motion through
space can be modeled precisely as that of a particle at his center of mass, which we will define
in Chapter 9. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a
maximum height of 1.85 m above the floor, and is at elevation 0.900 m when he touches down
again. Determine (a) his time of flight (his “hang time”), (b) his horizontal and (c) vertical
velocity components at the instant of takeoff, and (d) his takeoff angle. (e) For comparison,
determine the hang time of a whitetail deer making a jump with center-of-mass elevations yi =
1.20 m, ymax = 2.50 m, yf = 0.700 m.

Explanation / Answer

? the equation of star

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