1.two small charged objects attract each other with a force F when separated by

Question

1.two small charged objects attract each other with a force F when separated by a distance d. If the charge on each object is reduced to one-sixth of the original value and the distance between them is reduced to d/3, find an expression for the new force F in terms of the force, F

2.) A neutron consists of one 'up' quark of charge 2/3e and two 'down' quarks each having a charge -e/3. If we assume that the 'down' quarks are 2.6*10^-15m apart inside the neutron, what is the magnitude of the electrostatic force between them?

Explanation / Answer

1.
F = k * ( q1* q2) /d^2 ;
F1 = k * (q1/6 * q2/6 ) / [ (d/3 ) ^ 2 ] ;
F1 /F = { k * (q1/6 * q2/6 ) / [ (d/3 ) ^ 2 ] } / { k * ( q1* q2) /d^2 } ;
or F1 / F =( 1/ 36 ) * 3^2 = 0 .25
or F1 = 0.25 F ;

2 .
force between the down quarks = k [ ( e/3)^2 ] / ( 2.6 e -15 ) ^2 ;
=( 9 e 9 ) [ ( 1.6 e -19  / 3 ) ^ 2 ] / ( 2.6 e -15 ) ^2
= 3.786 N ,

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