A flatbed truck is carrying a heavy crate of mass 175 kg. The coefficient of sta

Question

A flatbed truck is carrying a heavy crate of mass 175 kg. The coefficient of static friction between the crate and the bed of the truck is 0.75.a) What is the normal force acting on the crate?
b) What is the maximum rate at which the driver can decelerate and still avoid having the crate
slide against the cab of the truck?
c) What is the maximum constant speed that the truck can have when going around a circular
horizontal curve that has a radius of 75 m and not have the crate slide on the truck?

Explanation / Answer

Mass, m = 175 kg

Coefficient of static friction, = 0.75

(a)

Normal force, N = m g

                        = 175 * 9.8

                        = 1715 N

(b)

maximum rate of acceleration, a = g

                                                 = 0.75 * 9.8

                                                 = 7.35 m/s^2

(c)

m v^2 / r = m a

v = sqrt ( a r )

    = sqrt ( 7.35 * 75 )

    = 23.5 m/s

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