A flatbed truck is carrying a 20.0-kg crate along a level road. The coefficient

Question

A flatbed truck is carrying a 20.0-kg crate along a level road. The coefficient of static friction between the crate and the bed is .400, and the coefficient of kinetic friction is .300. What is the maximum acceleration that the truck can have if the crate is to stay in place relative to the truck.

A. 8.00m/s^2, B. 78.5m/s^2, C. 3.92m/s^2, D. 196m/s^2, E. 7.84m/s^2

A bucket is being lowered by a very light rope with a constant downward velocity. The tension in the rope must be

A. less than the weight of the bucket

B. equal to the weight of the bucket

C. greater than the weight of the bucket

Explanation / Answer

here the required condition is static frictional force = net force = m*a

mu_s*m*g = m*amax

maximum accelaration is amax = mu_s*g = 0.4*9.81 = 3.92 m/s^2

So the correct option is C) 3.92 m/s^2

T+ (m*v^2/R)= m*g

Tension T = mg - (m*v^2/R)

v is the speed of the bucket

R is the length of the rope

So the correct option is A) less than the weight of the bucket

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