please explain in detail,, thanks in advance An RC circuit is made of a 2.2 kOhm

Question

please explain in detail,, thanks in advance

An RC circuit is made of a 2.2 kOhm resistor and a 0.001 microF capacitor. The circuit is connected to a 10V source of emf for 5 . 10-5 s. What is the resulting charge on the capacitor after that? Next, the capacitor is discraged through the resistor. How long will it lake for the charge to drop to 0.01 of the initial charge? Express your answer in both seconds and RC time units.

Explanation / Answer

C*V=Q=0.00000001 Coulombs--->0.001 E-6*2200=0.0000022 s=tau=2.2E-6 s q=Q*e^(-t/(R*C))=0.00000001*e(-5E-6/(2200*.001E-6))) new Q=1.3479E-18 Coulombs 1.3479E-18/.01=1.3479E-16 Coulombs 1.3479E-16/1.3479E-18=100 Ln(100)/-454545.5=t=0.00001013137 s--->10.13137E-6/454545.5=4.61 time constants tau=2.2E-6 s--->Q=0.01E-6 Coulombs 1% of original Q=1.3479E-16 Coulombs will take 10 E-6 s or 4.61 time constants

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