1. A physics book dropped from the top of the school takes 3.00 seconds to hit t
ID: 1693944 • Letter: 1
Question
1. A physics book dropped from the top of the school takes 3.00 seconds to hit the ground. How high is the school and how fast was the book traveling when it hit the ground?2. A ball rolls down a hill with constant a acceleration of 3 m/s2 (squared). If it starts from rest, what is its speed at the end of 4 seconds an how far did it move?
3. If I jump out of an airplane, and i am in the fictitious world of the physics book (no air), how long will it take me to reach a speed of 131.7 miles per hour and how far will I have traveled during that time?
4. A tennis ball is thrown vertically upward it returns to the starting point 6.0 seconds later. How high did the ball go?
5. Ryan's parents are out of town, so, of course, he throws a party. During the party, a priceless vase was knocked from a shelf 2.5 meters high and broke into several million pieces. There is not enough super glue in the world to put the vase back together. How long does it take the vase to hit the floor, how many miles per hour was it traveling when it hit the floor, and who does he blame for this?
6. Jenelle throws Matt's calculator vertically downward with an initial velocity of -4.9 m/s from the top of Enger Tower (19.6 meters high). Determine:
a. the velocity of the calculator just as it hits the ground --
b. the time the calculator is in the air ---
Don't know the formulas or do I understand these problems and have no book as a point of reference. Can you help me?
Explanation / Answer
Givne that the time tiken by the book to reach the ground is t = 3.00s Let h be height above ground where the book was dropped . And v be the velocity of the book just before hits ground ----------------------------------------------------------------------- Since the book released, initial vleocity is u = 0 Apply equation of motion v = u + at for this motion v = 0 + gt v = (9.8 m/s^2)(3.00s) v = 29.4 m/s Again apply equation of motion S = ut + (1/2)at^2 S = 0 + (1/2)gt^2 S = 0 + (1/2)(9.8 m/s^2)(3.00s)^2 S = 44.1 m
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