1. A pea plant is heterozygous for three genes (TtRrYy), where: T= tall, which i
ID: 10866 • Letter: 1
Question
1. A pea plant is heterozygous for three genes (TtRrYy), where:T= tall, which is dominant to t = dwarf
R= round seeds, which is dominant to r = wrinkled
Y = yellow seeds, which is dominant to y = green seeds
If this plant is self fertilized, what are the predicted phenotypes of the offspring and what fraction of the offspring will occur in each category?
Answer:
tall, round and yellow (28/64); tall, round, and green (8/64); tall, wrinkled, and yellow (9/64); dwarf, round, and yellow (9/64); dwarf, wrinkled and yellow (3/64); dwarf, round and green (3/64); tall, wrinkled and green (3/64); and dwarf, wrinkled, and green (1/64).
i dont understand this answer it does not seem to make sence with the rules of phynotypes. i thought it was 2^n which mean 2^3. overall i dont understand how to solve this problem.
Explanation / Answer
That because it is not right. the correct answer is: tall, round and yellow (27/64); tall, round, and green (9/64); tall, wrinkled, and yellow (9/64); dwarf, round, and yellow (9/64); dwarf, wrinkled and yellow (3/64); dwarf, round and green (3/64); tall, wrinkled and green (3/64); and dwarf, wrinkled, and green (1/64). multiply the probability of getting the first one by the second by the third. Example: probability of tall, round, and green tall, round, green (probability of tall (3/4), probability of round (3/4), probability of green (1/4) 3/4*3/4*1/4=9/64
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