Irons mass is 248.9g (m x), mass of calorimeter cup ( m cal )= 7.9 g accepted sp

Question

Irons mass is 248.9g (mx), mass of calorimeter cup ( mcal)= 7.9 g accepted specific heat of cup = 2J/g degree C mass of water inside calorimeter cup (mw)= 286.1 Txi= 100 degree C Twi= 23.9 degree c Txf= Twf= 31.2 degree C Find computed specific heat, accepted specific heat and PERCENT ERROR. FORMULA : Cx= [Cw mw (Twf-Twi) + Ccal mcal (Twf-Twi) ] / [mx ( Txi - Txf) ] please show all the work . Irons mass is 248.9g (mx), mass of calorimeter cup ( mcal)= 7.9 g accepted specific heat of cup = 2J/g degree C mass of water inside calorimeter cup (mw)= 286.1 Txi= 100 degree C Twi= 23.9 degree c Txf= Twf= 31.2 degree C Find computed specific heat, accepted specific heat and PERCENT ERROR. FORMULA : Cx= [Cw mw (Twf-Twi) + Ccal mcal (Twf-Twi) ] / [mx ( Txi - Txf) ] please show all the work .

Explanation / Answer

Irons mass is 248.9g (mx), mass of calorimeter cup ( mcal)= 7.9 g accepted specific heat of cup = 2J/g degree C mass of water inside calorimeter cup (mw)= 286.1 Specific heat of water Cw = 4.186 J/g degreeC Specific heat of calorimeter Ccal = 0.386 J/g degreeC Txi= 100 degree C Twi= 23.9 degree c Txf= Twf= 31.2 degree C Formula                  Cx= [Cw mw (Twf-Twi) + Ccal mcal (Twf-Twi) ] / [mx ( Txi - Txf) ]                      = [4.186*286.1(31.2-23.9) + 0.386*7.9*(31.2-23.9)]/[248.9(100 - 31.2)]                      = [(4.186*286.1*7.3) + (0.386*7.9*7.3)]/[248.9*68.8]                      = [ 8742.58658 + 22.26062]/[17124.32]                      =  8764.8472/17124.32                      = 0.51183 J/g degreeC    (It is the computed value) Accepted value C = 2 J/g degreeC Percent error = [|0.51183 - 2|/2] * 100                       = 74.40 %   Irons mass is 248.9g (mx), mass of calorimeter cup ( mcal)= 7.9 g accepted specific heat of cup = 2J/g degree C mass of water inside calorimeter cup (mw)= 286.1 Specific heat of water Cw = 4.186 J/g degreeC Specific heat of calorimeter Ccal = 0.386 J/g degreeC Txi= 100 degree C Twi= 23.9 degree c Txf= Twf= 31.2 degree C Formula                  Cx= [Cw mw (Twf-Twi) + Ccal mcal (Twf-Twi) ] / [mx ( Txi - Txf) ]                      = [4.186*286.1(31.2-23.9) + 0.386*7.9*(31.2-23.9)]/[248.9(100 - 31.2)]                      = [(4.186*286.1*7.3) + (0.386*7.9*7.3)]/[248.9*68.8]                      = [ 8742.58658 + 22.26062]/[17124.32]                      =  8764.8472/17124.32                      = 0.51183 J/g degreeC    (It is the computed value) Accepted value C = 2 J/g degreeC Percent error = [|0.51183 - 2|/2] * 100                       = 74.40 %  

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